{"id":1298,"date":"2017-08-22T15:40:26","date_gmt":"2017-08-22T15:40:26","guid":{"rendered":"http:\/\/curiealapitvany.hu\/?p=1298"},"modified":"2017-11-29T10:01:43","modified_gmt":"2017-11-29T10:01:43","slug":"felhivas-a-20172018-as-tanevi-curie-matematika-emlekversenyre","status":"publish","type":"post","link":"http:\/\/curiealapitvany.hu\/?p=1298","title":{"rendered":"Felh\u00edv\u00e1s a 2017\/2018-as tan\u00e9vi Curie Matematika Eml\u00e9kversenyre"},"content":{"rendered":"<p>A Curie Oktat\u00e1sfejleszt\u0151 \u00e9s Tehets\u00e9ggondoz\u00f3 K\u00f6zhaszn\u00fa Alap\u00edtv\u00e1ny \u00e9s a Magyar Tehets\u00e9ggondoz\u00f3 T\u00e1rsas\u00e1g k\u00e9mia \u00e9s\u00a0k\u00f6rnyezetv\u00e9delmi szekci\u00f3ja a 2017\/2018-as tan\u00e9vben is meghirdeti a Curie Matematika Eml\u00e9kversenyt: <!--more-->az \u00e1ltal\u00e1nos\u00a0iskol\u00e1k 3-4-5-6-7-8. oszt\u00e1lyos, 9. \u00e9s 10. \u00e9vfolyamos k\u00f6z\u00e9piskol\u00e1s (ill. m\u00e1s iskolat\u00edpusok ennek megfelel\u0151 \u00e9vfolyam\u00fa)\u00a0magyarorsz\u00e1gi \u00e9s hat\u00e1rainkon t\u00fali magyar tanul\u00f3i sz\u00e1m\u00e1ra.<\/p>\n<h2 style=\"text-align: center;\"><strong>Figyelem!<br \/>\n<\/strong><strong>A\u00a0Curie versenyek nevez\u00e9si hat\u00e1rideje<\/strong><span style=\"color: #ff0000;\"><strong><br \/>\n<\/strong><\/span><strong style=\"color: #ff0000;\">2017. okt\u00f3ber 31-re m\u00f3dosul.<\/strong><\/h2>\n<h3><span style=\"color: #ff0000;\"><strong><a style=\"color: #ff0000;\" href=\"http:\/\/curiealapitvany.hu\/wp-content\/uploads\/2017\/08\/Versenyfelh\u00edv\u00e1s-Matek-2017-2018.pdf\">A teljes versenyfelh\u00edv\u00e1s \u00e9s a r\u00e9szletek ide kattintva t\u00f6lthet\u0151ek le.<\/a><\/strong><\/span><\/h3>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A Curie Oktat\u00e1sfejleszt\u0151 \u00e9s Tehets\u00e9ggondoz\u00f3 K\u00f6zhaszn\u00fa Alap\u00edtv\u00e1ny \u00e9s a Magyar Tehets\u00e9ggondoz\u00f3 T\u00e1rsas\u00e1g k\u00e9mia \u00e9s\u00a0k\u00f6rnyezetv\u00e9delmi szekci\u00f3ja a 2017\/2018-as tan\u00e9vben is meghirdeti a Curie Matematika Eml\u00e9kversenyt:<\/p>\n","protected":false},"author":1,"featured_media":177,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[12,4],"tags":[9],"views":2711,"_links":{"self":[{"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/posts\/1298"}],"collection":[{"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1298"}],"version-history":[{"count":6,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/posts\/1298\/revisions"}],"predecessor-version":[{"id":1324,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/posts\/1298\/revisions\/1324"}],"wp:featuredmedia":[{"embeddable":true,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=\/wp\/v2\/media\/177"}],"wp:attachment":[{"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1298"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1298"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/curiealapitvany.hu\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1298"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}